| Bus Ticket Price: | $39 |
|---|---|
| Avg. Bus Duration: | 5h 30m |
| Bus Companies: | Hoosier Ride, Greyhound |
| Daily buses: | 2 |
| Buses depart from: | Lexington |
| Bus arrives in: | Evansville |
Information about the bus from Lexington to Evansville.
The travel length between Lexington and Evansville takes by bus around 5 hours and 30 minutes, and the approximate price for a bus ticket between Lexington and Evansville is $39.
Please note that this information about the bus from Lexington to Evansville is approximate. GoTicketio struggles to keep its database with updated information, but for accuracy of schedules, number of stops, travel time and price of bus tickets from Lexington to Evansville, you have to ask directly to the bus company you want to travel from Lexington to Evansville. The information GoTicketio provides its costumers about the bus from Lexington to Evansville is not official.
According to our database there is a direct bus route between Lexington and Evansville. Book now to not miss out! Take a look at the available schedules and use the calendar to choose your preferred travel date(s).
WJW Investments Bus Stop
Evansville Bus Station
5h 30m
$40
Hoosier Ride
WJW Investments Bus Stop
Evansville Bus Station
12h 50m
$51
Greyhound
If you want to get cheap bus tickets from Lexington to Evansville we recommend that you book in advance as the best Hoosier Ride, Greyhound tickets sell out fast.The cheapest ticket is usually $39 and the most expensive one to go to Evansville is approximately $51. .
The first bus leaves at 08:05 from Lexington and costs $40 while the last one arriving at Evansville costs $51 and it is at 02:55.
The companies that can help you are: Hoosier Ride, Greyhound.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
The approximate distance between the two places is 311 km. With the route we propose, it will take approximately 5h 30m.