Information about the train from Chipley to San Antonio. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Chipley to San Antonio. Best of all, getting from Chipley to San Antonio is budget-friendly, with train tickets starting at just $147. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Chipley to San Antonio is through Montgomery. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
You can find the most accurate information for the route Chipley FL - Montgomery AL by clicking here
Montgomery Station
San Antonio Station
68h 10m
$303
Amtrak Thruway
Montgomery Station
San Antonio Station
68h 10m
$331
Amtrak Thruway
If you want to get cheap train tickets from Chipley to San Antonio we recommend that you book in advance as the best Amtrak Thruway tickets sell out fast.The cheapest ticket is usually $147 and the most expensive one to go to San Antonio is approximately $331. .Remember that you must also add the cost of the journey: Chipley -> Montgomery
The first trains for the route we propose are:
Chipley -> Montgomery: -
Montgomery -> San Antonio: 01:45
The companies that can help you are: Amtrak Thruway.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Chipley -> Montgomery
2.- Montgomery -> San Antonio
The approximate distance between the two places is 1455 km. With the route we propose, it will take approximately 22h 20m (plus the time it takes to you to make: Chipley -> Montgomery).