Train Ticket Price: | $98 |
---|---|
Avg. Train Duration: | 15h 15m |
Train Companies: | Amtrak |
Daily Trains: | 8 |
Trains depart from: | Cleveland |
Trains arrive in: | East Peoria |
Information about the train from Cleveland to East Peoria. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Cleveland to East Peoria. Best of all, getting from Cleveland to East Peoria is budget-friendly, with train tickets starting at just $98. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database there is a direct train route between Cleveland and East Peoria. Book now to not miss out! Take a look at the available schedules and use the calendar to choose your preferred travel date(s).
Cleveland Station
East Peoria Station
16h 11m
$98
Amtrak
Cleveland Station
East Peoria Station
16h 11m
$104
Amtrak
Cleveland Station
East Peoria Station
16h 1m
$98
Amtrak
Cleveland Station
East Peoria Station
16h 1m
$104
Amtrak
Cleveland Station
East Peoria Station
15h 25m
$104
Amtrak
Cleveland Station
East Peoria Station
15h 15m
$104
Amtrak
Cleveland Station
East Peoria Station
15h 25m
$98
Amtrak
Cleveland Station
East Peoria Station
15h 15m
$98
Amtrak
If you want to get cheap train tickets from Cleveland to East Peoria we recommend that you book in advance as the best Amtrak tickets sell out fast.The cheapest ticket is usually $98 and the most expensive one to go to East Peoria is approximately $104. .
The first train leaves at 02:59 from Cleveland and costs $98 while the last one arriving at East Peoria costs $98 and it is at 18:00.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
The approximate distance between the two places is 774 km. With the route we propose, it will take approximately 15h 15m.