| Train Ticket Price: | $179 |
|---|---|
| Avg. Train Duration: | 21h 1m |
| Train Companies: | Amtrak |
| Daily Trains: | 1 |
| Trains depart from: | Cleveland Heights |
| Trains arrive in: | Frostburg |
Information about the train from Cleveland Heights to Frostburg. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Cleveland Heights to Frostburg. Best of all, getting from Cleveland Heights to Frostburg is budget-friendly, with train tickets starting at just $179. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Cleveland Heights to Frostburg is through Martinsburg. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Cleveland Heights Station
Martinsburg Station
9h 7m
$61
Amtrak
Martinsburg, WV (MRB)
Frostburg, MD - Frostburg State University (FSB)
11h 54m
$130
Amtrak
If you want to get cheap train tickets from Cleveland Heights to Frostburg we recommend that you book in advance as the best Amtrak tickets sell out fast.The cheapest ticket is usually $179 and the most expensive one to go to Frostburg is approximately $191. .
The first train leaves at 01:54 from Cleveland Heights and costs $61 while the last one arriving at Frostburg costs $130 and it is at 22:55.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Cleveland Heights -> Martinsburg
2.- Martinsburg -> Frostburg
The approximate distance between the two places is 352 km. With the route we propose, it will take approximately 21h 1m.