Train Ticket Price: | $97.5 |
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Avg. Train Duration: | 20h 1m |
Train Companies: | Amtrak |
Daily Trains: | 2 |
Trains depart from: | Davenport |
Trains arrive in: | Cleveland Heights |
Information about the train from Davenport to Cleveland Heights. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Davenport to Cleveland Heights. Best of all, getting from Davenport to Cleveland Heights is budget-friendly, with train tickets starting at just $97.5. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Davenport to Cleveland Heights is through Plano. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Plano Station
Cleveland Heights Station
19h 13m
$65.5
Amtrak
Plano Station
Cleveland Heights Station
15h 23m
$80.5
Amtrak
If you want to get cheap train tickets from Davenport to Cleveland Heights we recommend that you book in advance as the best Amtrak tickets sell out fast.The cheapest ticket is usually $97.5 and the most expensive one to go to Cleveland Heights is approximately $112.5. .
The first train leaves at 16:00 from Davenport and costs $32 while the last one arriving at Cleveland Heights costs $80.5 and it is at 01:45.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Davenport -> Plano
2.- Plano -> Cleveland Heights
The approximate distance between the two places is 871 km. With the route we propose, it will take approximately 20h 1m.