Train Ticket Price: | $235 |
---|---|
Avg. Train Duration: | 24h 20m |
Train Companies: | Amtrak |
Daily Trains: | 2 |
Trains depart from: | Dearborn Heights |
Trains arrive in: | Hancock |
Information about the train from Dearborn Heights to Hancock. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Dearborn Heights to Hancock. Best of all, getting from Dearborn Heights to Hancock is budget-friendly, with train tickets starting at just $235. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Dearborn Heights to Hancock is through Harrisburg. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Dearborn Heights Station
Harrisburg Station
30h 5m
$230
Amtrak
Dearborn Heights Station
Harrisburg Station
15h 45m
$174
Amtrak
Harrisburg, PA (HAR)
Hancock, MD (HNK)
8h 35m
$124
Amtrak
If you want to get cheap train tickets from Dearborn Heights to Hancock we recommend that you book in advance as the best Amtrak tickets sell out fast.The cheapest ticket is usually $235 and the most expensive one to go to Hancock is approximately $354. .
The first train leaves at 06:50 from Dearborn Heights and costs $230 while the last one arriving at Hancock costs $124 and it is at 21:40.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Dearborn Heights -> Harrisburg
2.- Harrisburg -> Hancock
The approximate distance between the two places is 601 km. With the route we propose, it will take approximately 24h 20m.