| Train Ticket Price: | $172 |
|---|---|
| Avg. Train Duration: | 28h 20m |
| Train Companies: | Amtrak |
| Daily Trains: | 2 |
| Trains depart from: | Eau Claire |
| Trains arrive in: | Cleveland Heights |
Information about the train from Eau Claire to Cleveland Heights. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Eau Claire to Cleveland Heights. Best of all, getting from Eau Claire to Cleveland Heights is budget-friendly, with train tickets starting at just $172. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Eau Claire to Cleveland Heights is through St. Cloud. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Eau Claire, WI - University of Wisconsin (EUC)
St. Cloud, MN (SCD)
8h 54m
$37
Amtrak
St. Cloud Station
Cleveland Heights Station
19h 26m
$135
Amtrak
St. Cloud Station
Cleveland Heights Station
23h 16m
$135
Amtrak
If you want to get cheap train tickets from Eau Claire to Cleveland Heights we recommend that you book in advance as the best Amtrak tickets sell out fast.The price of the ticket is usually $172.
The first train leaves at 15:30 from Eau Claire and costs $37 while the last one arriving at Cleveland Heights costs $135 and it is at 05:35.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Eau Claire -> St. Cloud
2.- St. Cloud -> Cleveland Heights
The approximate distance between the two places is 1026 km. With the route we propose, it will take approximately 28h 20m.