| Train Ticket Price: | $149.5 |
|---|---|
| Avg. Train Duration: | 23h 4m |
| Train Companies: | Amtrak Thruway, Amtrak |
| Daily Trains: | 2 |
| Trains depart from: | Greenville |
| Trains arrive in: | Ledyard |
Information about the train from Greenville to Ledyard. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Greenville to Ledyard. Best of all, getting from Greenville to Ledyard is budget-friendly, with train tickets starting at just $149.5. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Greenville to Ledyard is through Norfolk. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Norfolk Station
Ledyard Station
15h 5m
$92.5
Amtrak Thruway
Norfolk Station
Ledyard Station
15h 40m
$92.5
Amtrak Thruway
If you want to get cheap train tickets from Greenville to Ledyard we recommend that you book in advance as the best Amtrak Thruway, Amtrak tickets sell out fast.The cheapest ticket is usually $149.5 and the most expensive one to go to Ledyard is approximately $157.5. .
The first train leaves at 12:37 from Greenville and costs $65 while the last one arriving at Ledyard costs $92.5 and it is at 06:55.
The companies that can help you are: Amtrak Thruway, Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Greenville -> Norfolk
2.- Norfolk -> Ledyard
The approximate distance between the two places is 925 km. With the route we propose, it will take approximately 23h 4m.