Information about the train from Indianapolis to Bixby. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Indianapolis to Bixby. Best of all, getting from Indianapolis to Bixby is budget-friendly, with train tickets starting at just $163. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Indianapolis to Bixby is through Oklahoma City. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Indianapolis, IN (IND)
Oklahoma City, OK (OKC)
40h 27m
$163
Amtrak
Indianapolis, IN (IND)
Oklahoma City, OK (OKC)
25h 20m
$176
Amtrak
You can find the most accurate information for the route Oklahoma City OK - Bixby OK by clicking here
If you want to get cheap train tickets from Indianapolis to Bixby we recommend that you book in advance as the best Amtrak tickets sell out fast.The cheapest ticket is usually $163 and the most expensive one to go to Bixby is approximately $176. .Remember that you must also add the cost of the journey: Oklahoma City -> Bixby
The first trains for the route we propose are:
Indianapolis -> Oklahoma City: 06:00
Oklahoma City -> Bixby: -
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Indianapolis -> Oklahoma City
2.- Oklahoma City -> Bixby
The approximate distance between the two places is 1106 km. With the route we propose, it will take approximately 25h 20m (plus the time it takes to you to make: Oklahoma City -> Bixby).