Information about the train from Northglenn to Newton. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Northglenn to Newton. Best of all, getting from Northglenn to Newton is budget-friendly, with train tickets starting at just $191. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Northglenn to Newton is through Fraser. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
| Instructions | Station | Distance | Duration |
|---|---|---|---|
| Bus towards Union Stn | 104th Ave & Grant Dr | 16.1km | 20m |
| Union Station | |||
| Regional Transportation District | |||
| Walk to Union Station (DEN) | 0.0km | 1m | |
| Train towards Emeryville Amtrak | Union Station (DEN) | 100.1km | 2h 2m |
| Fraser Station | |||
| Amtrak | |||
If you want to get cheap train tickets from Northglenn to Newton we recommend that you book in advance as the best Amtrak tickets sell out fast.The price of the ticket is usually $191.Remember that you must also add the cost of the journey: Northglenn -> Fraser
The first trains for the route we propose are:
Northglenn -> Fraser: -
Fraser -> Newton: 15:50
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Northglenn -> Fraser
2.- Fraser -> Newton
The approximate distance between the two places is 801 km. With the route we propose, it will take approximately 36h 18m (plus the time it takes to you to make: Northglenn -> Fraser).