| Train Ticket Price: | $163 |
|---|---|
| Avg. Train Duration: | 14h 56m |
| Train Companies: | Amtrak, Amtrak Thruway |
| Daily Trains: | 1 |
| Trains depart from: | Salisbury |
| Trains arrive in: | Kinston |
Information about the train from Salisbury to Kinston. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Salisbury to Kinston. Best of all, getting from Salisbury to Kinston is budget-friendly, with train tickets starting at just $163. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Salisbury to Kinston is through Newport News. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Salisbury Station
Newport News Station
9h 32m
$123
Amtrak Thruway
Newport News Station
Kinston Station
7h 25m
$62
Amtrak
If you want to get cheap train tickets from Salisbury to Kinston we recommend that you book in advance as the best Amtrak, Amtrak Thruway tickets sell out fast.The cheapest ticket is usually $163 and the most expensive one to go to Kinston is approximately $185. .
The first train leaves at 09:20 from Salisbury and costs $123 while the last one arriving at Kinston costs $62 and it is at 16:25.
The companies that can help you are: Amtrak, Amtrak Thruway.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Salisbury -> Newport News
2.- Newport News -> Kinston
The approximate distance between the two places is 449 km. With the route we propose, it will take approximately 14h 56m.