Information about the train from South Milwaukee to Rogers. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from South Milwaukee to Rogers. Best of all, getting from South Milwaukee to Rogers is budget-friendly, with train tickets starting at just $103. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from South Milwaukee to Rogers is through Little Rock. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
South Milwaukee Station
Little Rock Station
16h 2m
$124
Amtrak
South Milwaukee Station
Little Rock Station
15h 52m
$124
Amtrak
You can find the most accurate information for the route Little Rock AR - Rogers AR by clicking here
If you want to get cheap train tickets from South Milwaukee to Rogers we recommend that you book in advance as the best Amtrak tickets sell out fast.The cheapest ticket is usually $103 and the most expensive one to go to Rogers is approximately $124. .Remember that you must also add the cost of the journey: Little Rock -> Rogers
The first trains for the route we propose are:
South Milwaukee -> Little Rock: 11:00
Little Rock -> Rogers: -
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- South Milwaukee -> Little Rock
2.- Little Rock -> Rogers
The approximate distance between the two places is 1051 km. With the route we propose, it will take approximately 15h 52m (plus the time it takes to you to make: Little Rock -> Rogers).