| Train Ticket Price: | $165 |
|---|---|
| Avg. Train Duration: | 27h 29m |
| Train Companies: | Amtrak |
| Daily Trains: | 2 |
| Trains depart from: | Allentown |
| Trains arrive in: | Rockford |
Information about the train from Allentown to Rockford. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Allentown to Rockford. Best of all, getting from Allentown to Rockford is budget-friendly, with train tickets starting at just $165. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Allentown to Rockford is through Cleveland. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Allentown, PA (AWN)
Cleveland, OH (CLE)
18h 57m
$295
Amtrak
Cleveland Station
Rockford Station
10h 11m
$78
Amtrak
Cleveland Station
Rockford Station
10h 55m
$78
Amtrak
If you want to get cheap train tickets from Allentown to Rockford we recommend that you book in advance as the best Amtrak tickets sell out fast.The cheapest ticket is usually $165 and the most expensive one to go to Rockford is approximately $373. .
The first train leaves at 08:30 from Allentown and costs $295 while the last one arriving at Rockford costs $78 and it is at 13:40.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Allentown -> Cleveland
2.- Cleveland -> Rockford
The approximate distance between the two places is 1331 km. With the route we propose, it will take approximately 27h 29m.