Train Ticket Price: | $213 |
---|---|
Avg. Train Duration: | 50h 40m |
Train Companies: | Amtrak |
Daily Trains: | 1 |
Trains depart from: | East Moline |
Trains arrive in: | San Bernardino |
Information about the train from East Moline to San Bernardino. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from East Moline to San Bernardino. Best of all, getting from East Moline to San Bernardino is budget-friendly, with train tickets starting at just $213. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from East Moline to San Bernardino is through Kewanee. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
East Moline Station
Kewanee Station
3h 5m
$27.5
Amtrak
Kewanee Station
San Bernardino Station
47h 35m
$190
Amtrak
If you want to get cheap train tickets from East Moline to San Bernardino we recommend that you book in advance as the best Amtrak tickets sell out fast.The cheapest ticket is usually $213 and the most expensive one to go to San Bernardino is approximately $217.5. .
The first train leaves at 16:20 from East Moline and costs $27.5 while the last one arriving at San Bernardino costs $190 and it is at 05:42.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- East Moline -> Kewanee
2.- Kewanee -> San Bernardino
The approximate distance between the two places is 2884 km. With the route we propose, it will take approximately 50h 40m.