| Train Ticket Price: | $181 |
|---|---|
| Avg. Train Duration: | 19h 42m |
| Train Companies: | Amtrak Thruway, Amtrak |
| Daily Trains: | 1 |
| Trains depart from: | Hancock |
| Trains arrive in: | Cleveland Heights |
Information about the train from Hancock to Cleveland Heights. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Hancock to Cleveland Heights. Best of all, getting from Hancock to Cleveland Heights is budget-friendly, with train tickets starting at just $181. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Hancock to Cleveland Heights is through Harrisburg. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Hancock Station
Harrisburg Station
7h 25m
$170
Amtrak Thruway
Harrisburg Station
Cleveland Heights Station
12h 17m
$73
Amtrak
If you want to get cheap train tickets from Hancock to Cleveland Heights we recommend that you book in advance as the best Amtrak Thruway, Amtrak tickets sell out fast.The cheapest ticket is usually $181 and the most expensive one to go to Cleveland Heights is approximately $243. .
The first train leaves at 10:05 from Hancock and costs $170 while the last one arriving at Cleveland Heights costs $73 and it is at 02:53.
The companies that can help you are: Amtrak Thruway, Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Hancock -> Harrisburg
2.- Harrisburg -> Cleveland Heights
The approximate distance between the two places is 405 km. With the route we propose, it will take approximately 19h 42m.