| Train Ticket Price: | $212 |
|---|---|
| Avg. Train Duration: | 24h 39m |
| Train Companies: | Amtrak Thruway, Amtrak |
| Daily Trains: | 1 |
| Trains depart from: | Hancock |
| Trains arrive in: | Dearborn Heights |
Information about the train from Hancock to Dearborn Heights. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Hancock to Dearborn Heights. Best of all, getting from Hancock to Dearborn Heights is budget-friendly, with train tickets starting at just $212. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Hancock to Dearborn Heights is through Harrisburg. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Hancock Station
Harrisburg Station
7h 25m
$170
Amtrak Thruway
Harrisburg Station
Dearborn Heights Station
17h 14m
$89
Amtrak
If you want to get cheap train tickets from Hancock to Dearborn Heights we recommend that you book in advance as the best Amtrak Thruway, Amtrak tickets sell out fast.The cheapest ticket is usually $212 and the most expensive one to go to Dearborn Heights is approximately $259. .
The first train leaves at 10:05 from Hancock and costs $170 while the last one arriving at Dearborn Heights costs $89 and it is at 07:50.
The companies that can help you are: Amtrak Thruway, Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Hancock -> Harrisburg
2.- Harrisburg -> Dearborn Heights
The approximate distance between the two places is 601 km. With the route we propose, it will take approximately 24h 39m.