| Train Ticket Price: | $163 |
|---|---|
| Avg. Train Duration: | 32h 7m |
| Train Companies: | Amtrak |
| Daily Trains: | 2 |
| Trains depart from: | Jefferson City |
| Trains arrive in: | Lancaster |
Information about the train from Jefferson City to Lancaster. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Jefferson City to Lancaster. Best of all, getting from Jefferson City to Lancaster is budget-friendly, with train tickets starting at just $163. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Jefferson City to Lancaster is through Normal. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Jefferson City, MO (JEF)
Bloomington-Normal, IL - Uptown Station (BNL)
6h 35m
$101
Amtrak
Normal Station
Lancaster Station
25h 32m
$178
Amtrak
Normal Station
Lancaster Station
25h 32m
$194
Amtrak
If you want to get cheap train tickets from Jefferson City to Lancaster we recommend that you book in advance as the best Amtrak tickets sell out fast.The cheapest ticket is usually $163 and the most expensive one to go to Lancaster is approximately $295. .
The first train leaves at 11:18 from Jefferson City and costs $101 while the last one arriving at Lancaster costs $194 and it is at 13:40.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Jefferson City -> Normal
2.- Normal -> Lancaster
The approximate distance between the two places is 1593 km. With the route we propose, it will take approximately 32h 7m.