| Train Ticket Price: | $146 |
|---|---|
| Avg. Train Duration: | 24h 53m |
| Train Companies: | Amtrak |
| Daily Trains: | 4 |
| Trains depart from: | Oshkosh |
| Trains arrive in: | Hancock |
Information about the train from Oshkosh to Hancock. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Oshkosh to Hancock. Best of all, getting from Oshkosh to Hancock is budget-friendly, with train tickets starting at just $146. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Oshkosh to Hancock is through Portage. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Oshkosh Station
Portage Station
6h 36m
$31
Amtrak
Oshkosh Station
Portage Station
6h 36m
$44
Amtrak
Oshkosh Station
Portage Station
6h 26m
$31
Amtrak
Oshkosh Station
Portage Station
6h 26m
$44
Amtrak
If you want to get cheap train tickets from Oshkosh to Hancock we recommend that you book in advance as the best Amtrak tickets sell out fast.The cheapest ticket is usually $146 and the most expensive one to go to Hancock is approximately $159. .
The first train leaves at 10:55 from Oshkosh and costs $31 while the last one arriving at Hancock costs $115 and it is at 07:54.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Oshkosh -> Portage
2.- Portage -> Hancock
The approximate distance between the two places is 400 km. With the route we propose, it will take approximately 24h 53m.