| Train Ticket Price: | $101.5 |
|---|---|
| Avg. Train Duration: | 18h 16m |
| Train Companies: | Amtrak |
| Daily Trains: | 2 |
| Trains depart from: | Waterloo |
| Trains arrive in: | Cadillac |
Information about the train from Waterloo to Cadillac. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Waterloo to Cadillac. Best of all, getting from Waterloo to Cadillac is budget-friendly, with train tickets starting at just $101.5. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Waterloo to Cadillac is through Battle Creek. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Waterloo Station
Battle Creek Station
13h 9m
$97
Amtrak
Waterloo Station
Battle Creek Station
12h 12m
$97
Amtrak
Battle Creek Station
Cadillac Station
10h
$42.5
Amtrak
Battle Creek Station
Cadillac Station
9h 9m
$42.5
Amtrak
If you want to get cheap train tickets from Waterloo to Cadillac we recommend that you book in advance as the best Amtrak tickets sell out fast.The cheapest ticket is usually $101.5 and the most expensive one to go to Cadillac is approximately $139.5. .
The first train leaves at 06:36 from Waterloo and costs $97 while the last one arriving at Cadillac costs $42.5 and it is at 19:01.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Waterloo -> Battle Creek
2.- Battle Creek -> Cadillac
The approximate distance between the two places is 365 km. With the route we propose, it will take approximately 18h 16m.