| Train Ticket Price: | $196 |
|---|---|
| Avg. Train Duration: | 39h 2m |
| Train Companies: | Amtrak |
| Daily Trains: | 1 |
| Trains depart from: | Jefferson City |
| Trains arrive in: | Glenwood Springs |
Information about the train from Jefferson City to Glenwood Springs. The train is one of the safest modes of transportation in existence, and offers a comfortable atmosphere for you to relax on your journey from Jefferson City to Glenwood Springs. Best of all, getting from Jefferson City to Glenwood Springs is budget-friendly, with train tickets starting at just $196. This is an estimate, so please contact the train ticket seller directly for precise information.
According to our database, the best route to go from Jefferson City to Glenwood Springs is through Lawrence. Take a look at the route we propose for this trip. We show you all available schedules for each train trip.
Jefferson City, MO (JEF)
Lawrence, KS (LRC)
5h 25m
$41
Amtrak
Lawrence, KS (LRC)
Glenwood Springs, CO (GSC)
33h 37m
$263
Amtrak
If you want to get cheap train tickets from Jefferson City to Glenwood Springs we recommend that you book in advance as the best Amtrak tickets sell out fast.The cheapest ticket is usually $196 and the most expensive one to go to Glenwood Springs is approximately $304. .
The first train leaves at 18:22 from Jefferson City and costs $41 while the last one arriving at Glenwood Springs costs $263 and it is at 13:46.
The companies that can help you are: Amtrak.
Each company has its rules and depending on the ticket, price, and offer different refund policies apply. We recommend that you contact the company where you bought the ticket to get a solution.
In Goticket we try to give a solution for every trip the user asks. Sometimes is not possible but we do our best to group different train direct routes to in order to create a multi-step journey that satisfies the user. This is the route we recommend::
1.- Jefferson City -> Lawrence
2.- Lawrence -> Glenwood Springs
The approximate distance between the two places is 1521 km. With the route we propose, it will take approximately 39h 2m.